Optimal. Leaf size=160 \[ -\frac {b^3 \left (10 a^2+5 a b+b^2\right ) \coth ^5(c+d x)}{5 d}-\frac {b^2 \left (10 a^3+10 a^2 b+5 a b^2+b^3\right ) \coth ^3(c+d x)}{3 d}-\frac {b \left (5 a^4+10 a^3 b+10 a^2 b^2+5 a b^3+b^4\right ) \coth (c+d x)}{d}-\frac {b^4 (5 a+b) \coth ^7(c+d x)}{7 d}+x (a+b)^5-\frac {b^5 \coth ^9(c+d x)}{9 d} \]
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Rubi [A] time = 0.09, antiderivative size = 160, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {3661, 390, 206} \[ -\frac {b^3 \left (10 a^2+5 a b+b^2\right ) \coth ^5(c+d x)}{5 d}-\frac {b^2 \left (10 a^2 b+10 a^3+5 a b^2+b^3\right ) \coth ^3(c+d x)}{3 d}-\frac {b \left (10 a^2 b^2+10 a^3 b+5 a^4+5 a b^3+b^4\right ) \coth (c+d x)}{d}-\frac {b^4 (5 a+b) \coth ^7(c+d x)}{7 d}+x (a+b)^5-\frac {b^5 \coth ^9(c+d x)}{9 d} \]
Antiderivative was successfully verified.
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Rule 206
Rule 390
Rule 3661
Rubi steps
\begin {align*} \int \left (a+b \coth ^2(c+d x)\right )^5 \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\left (a+b x^2\right )^5}{1-x^2} \, dx,x,\coth (c+d x)\right )}{d}\\ &=\frac {\operatorname {Subst}\left (\int \left (-b \left (5 a^4+10 a^3 b+10 a^2 b^2+5 a b^3+b^4\right )-b^2 \left (10 a^3+10 a^2 b+5 a b^2+b^3\right ) x^2-b^3 \left (10 a^2+5 a b+b^2\right ) x^4-b^4 (5 a+b) x^6-b^5 x^8+\frac {(a+b)^5}{1-x^2}\right ) \, dx,x,\coth (c+d x)\right )}{d}\\ &=-\frac {b \left (5 a^4+10 a^3 b+10 a^2 b^2+5 a b^3+b^4\right ) \coth (c+d x)}{d}-\frac {b^2 \left (10 a^3+10 a^2 b+5 a b^2+b^3\right ) \coth ^3(c+d x)}{3 d}-\frac {b^3 \left (10 a^2+5 a b+b^2\right ) \coth ^5(c+d x)}{5 d}-\frac {b^4 (5 a+b) \coth ^7(c+d x)}{7 d}-\frac {b^5 \coth ^9(c+d x)}{9 d}+\frac {(a+b)^5 \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\coth (c+d x)\right )}{d}\\ &=(a+b)^5 x-\frac {b \left (5 a^4+10 a^3 b+10 a^2 b^2+5 a b^3+b^4\right ) \coth (c+d x)}{d}-\frac {b^2 \left (10 a^3+10 a^2 b+5 a b^2+b^3\right ) \coth ^3(c+d x)}{3 d}-\frac {b^3 \left (10 a^2+5 a b+b^2\right ) \coth ^5(c+d x)}{5 d}-\frac {b^4 (5 a+b) \coth ^7(c+d x)}{7 d}-\frac {b^5 \coth ^9(c+d x)}{9 d}\\ \end {align*}
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Mathematica [A] time = 2.90, size = 231, normalized size = 1.44 \[ -\frac {b^5 \coth ^9(c+d x) \left (\frac {1575 a^4 \tanh ^8(c+d x)}{b^4}+\frac {1050 a^3 \left (3 \tanh ^2(c+d x)+1\right ) \tanh ^6(c+d x)}{b^3}+\frac {210 a^2 \left (15 \tanh ^4(c+d x)+5 \tanh ^2(c+d x)+3\right ) \tanh ^4(c+d x)}{b^2}-\frac {315 (a+b)^5 \tanh ^{-1}\left (\sqrt {\tanh ^2(c+d x)}\right ) \tanh ^{10}(c+d x)}{b^5 \sqrt {\tanh ^2(c+d x)}}+\frac {15 a \left (105 \tanh ^6(c+d x)+35 \tanh ^4(c+d x)+21 \tanh ^2(c+d x)+15\right ) \tanh ^2(c+d x)}{b}+315 \tanh ^8(c+d x)+105 \tanh ^6(c+d x)+63 \tanh ^4(c+d x)+45 \tanh ^2(c+d x)+35\right )}{315 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.43, size = 2111, normalized size = 13.19 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.31, size = 721, normalized size = 4.51 \[ \frac {315 \, {\left (a^{5} + 5 \, a^{4} b + 10 \, a^{3} b^{2} + 10 \, a^{2} b^{3} + 5 \, a b^{4} + b^{5}\right )} {\left (d x + c\right )} - \frac {2 \, {\left (1575 \, a^{4} b e^{\left (16 \, d x + 16 \, c\right )} + 6300 \, a^{3} b^{2} e^{\left (16 \, d x + 16 \, c\right )} + 9450 \, a^{2} b^{3} e^{\left (16 \, d x + 16 \, c\right )} + 6300 \, a b^{4} e^{\left (16 \, d x + 16 \, c\right )} + 1575 \, b^{5} e^{\left (16 \, d x + 16 \, c\right )} - 12600 \, a^{4} b e^{\left (14 \, d x + 14 \, c\right )} - 44100 \, a^{3} b^{2} e^{\left (14 \, d x + 14 \, c\right )} - 56700 \, a^{2} b^{3} e^{\left (14 \, d x + 14 \, c\right )} - 31500 \, a b^{4} e^{\left (14 \, d x + 14 \, c\right )} - 6300 \, b^{5} e^{\left (14 \, d x + 14 \, c\right )} + 44100 \, a^{4} b e^{\left (12 \, d x + 12 \, c\right )} + 136500 \, a^{3} b^{2} e^{\left (12 \, d x + 12 \, c\right )} + 161700 \, a^{2} b^{3} e^{\left (12 \, d x + 12 \, c\right )} + 90300 \, a b^{4} e^{\left (12 \, d x + 12 \, c\right )} + 21000 \, b^{5} e^{\left (12 \, d x + 12 \, c\right )} - 88200 \, a^{4} b e^{\left (10 \, d x + 10 \, c\right )} - 245700 \, a^{3} b^{2} e^{\left (10 \, d x + 10 \, c\right )} - 283500 \, a^{2} b^{3} e^{\left (10 \, d x + 10 \, c\right )} - 157500 \, a b^{4} e^{\left (10 \, d x + 10 \, c\right )} - 31500 \, b^{5} e^{\left (10 \, d x + 10 \, c\right )} + 110250 \, a^{4} b e^{\left (8 \, d x + 8 \, c\right )} + 283500 \, a^{3} b^{2} e^{\left (8 \, d x + 8 \, c\right )} + 325080 \, a^{2} b^{3} e^{\left (8 \, d x + 8 \, c\right )} + 175140 \, a b^{4} e^{\left (8 \, d x + 8 \, c\right )} + 39438 \, b^{5} e^{\left (8 \, d x + 8 \, c\right )} - 88200 \, a^{4} b e^{\left (6 \, d x + 6 \, c\right )} - 216300 \, a^{3} b^{2} e^{\left (6 \, d x + 6 \, c\right )} - 244020 \, a^{2} b^{3} e^{\left (6 \, d x + 6 \, c\right )} - 131460 \, a b^{4} e^{\left (6 \, d x + 6 \, c\right )} - 26292 \, b^{5} e^{\left (6 \, d x + 6 \, c\right )} + 44100 \, a^{4} b e^{\left (4 \, d x + 4 \, c\right )} + 107100 \, a^{3} b^{2} e^{\left (4 \, d x + 4 \, c\right )} + 117180 \, a^{2} b^{3} e^{\left (4 \, d x + 4 \, c\right )} + 63540 \, a b^{4} e^{\left (4 \, d x + 4 \, c\right )} + 13968 \, b^{5} e^{\left (4 \, d x + 4 \, c\right )} - 12600 \, a^{4} b e^{\left (2 \, d x + 2 \, c\right )} - 31500 \, a^{3} b^{2} e^{\left (2 \, d x + 2 \, c\right )} - 34020 \, a^{2} b^{3} e^{\left (2 \, d x + 2 \, c\right )} - 17460 \, a b^{4} e^{\left (2 \, d x + 2 \, c\right )} - 3492 \, b^{5} e^{\left (2 \, d x + 2 \, c\right )} + 1575 \, a^{4} b + 4200 \, a^{3} b^{2} + 4830 \, a^{2} b^{3} + 2640 \, a b^{4} + 563 \, b^{5}\right )}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} - 1\right )}^{9}}}{315 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 472, normalized size = 2.95 \[ -\frac {\left (\coth ^{5}\left (d x +c \right )\right ) a \,b^{4}}{d}-\frac {2 \left (\coth ^{5}\left (d x +c \right )\right ) a^{2} b^{3}}{d}-\frac {5 \left (\coth ^{7}\left (d x +c \right )\right ) a \,b^{4}}{7 d}-\frac {10 \left (\coth ^{3}\left (d x +c \right )\right ) a^{3} b^{2}}{3 d}-\frac {10 \left (\coth ^{3}\left (d x +c \right )\right ) a^{2} b^{3}}{3 d}+\frac {5 \ln \left (\coth \left (d x +c \right )+1\right ) a^{3} b^{2}}{d}+\frac {5 \ln \left (\coth \left (d x +c \right )+1\right ) a \,b^{4}}{2 d}-\frac {5 a^{4} b \coth \left (d x +c \right )}{d}-\frac {5 \ln \left (\coth \left (d x +c \right )-1\right ) a \,b^{4}}{2 d}+\frac {5 \ln \left (\coth \left (d x +c \right )+1\right ) a^{4} b}{2 d}-\frac {5 \ln \left (\coth \left (d x +c \right )-1\right ) a^{3} b^{2}}{d}-\frac {5 \ln \left (\coth \left (d x +c \right )-1\right ) a^{2} b^{3}}{d}-\frac {10 a^{2} b^{3} \coth \left (d x +c \right )}{d}-\frac {5 a \,b^{4} \coth \left (d x +c \right )}{d}+\frac {\ln \left (\coth \left (d x +c \right )+1\right ) a^{5}}{2 d}-\frac {\ln \left (\coth \left (d x +c \right )-1\right ) a^{5}}{2 d}-\frac {\ln \left (\coth \left (d x +c \right )-1\right ) b^{5}}{2 d}+\frac {\ln \left (\coth \left (d x +c \right )+1\right ) b^{5}}{2 d}-\frac {b^{5} \coth \left (d x +c \right )}{d}-\frac {5 \left (\coth ^{3}\left (d x +c \right )\right ) a \,b^{4}}{3 d}-\frac {10 a^{3} b^{2} \coth \left (d x +c \right )}{d}-\frac {5 \ln \left (\coth \left (d x +c \right )-1\right ) a^{4} b}{2 d}+\frac {5 \ln \left (\coth \left (d x +c \right )+1\right ) a^{2} b^{3}}{d}-\frac {b^{5} \left (\coth ^{9}\left (d x +c \right )\right )}{9 d}-\frac {\left (\coth ^{5}\left (d x +c \right )\right ) b^{5}}{5 d}-\frac {\left (\coth ^{3}\left (d x +c \right )\right ) b^{5}}{3 d}-\frac {\left (\coth ^{7}\left (d x +c \right )\right ) b^{5}}{7 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.36, size = 624, normalized size = 3.90 \[ \frac {1}{315} \, b^{5} {\left (315 \, x + \frac {315 \, c}{d} - \frac {2 \, {\left (3492 \, e^{\left (-2 \, d x - 2 \, c\right )} - 13968 \, e^{\left (-4 \, d x - 4 \, c\right )} + 26292 \, e^{\left (-6 \, d x - 6 \, c\right )} - 39438 \, e^{\left (-8 \, d x - 8 \, c\right )} + 31500 \, e^{\left (-10 \, d x - 10 \, c\right )} - 21000 \, e^{\left (-12 \, d x - 12 \, c\right )} + 6300 \, e^{\left (-14 \, d x - 14 \, c\right )} - 1575 \, e^{\left (-16 \, d x - 16 \, c\right )} - 563\right )}}{d {\left (9 \, e^{\left (-2 \, d x - 2 \, c\right )} - 36 \, e^{\left (-4 \, d x - 4 \, c\right )} + 84 \, e^{\left (-6 \, d x - 6 \, c\right )} - 126 \, e^{\left (-8 \, d x - 8 \, c\right )} + 126 \, e^{\left (-10 \, d x - 10 \, c\right )} - 84 \, e^{\left (-12 \, d x - 12 \, c\right )} + 36 \, e^{\left (-14 \, d x - 14 \, c\right )} - 9 \, e^{\left (-16 \, d x - 16 \, c\right )} + e^{\left (-18 \, d x - 18 \, c\right )} - 1\right )}}\right )} + \frac {1}{21} \, a b^{4} {\left (105 \, x + \frac {105 \, c}{d} - \frac {8 \, {\left (203 \, e^{\left (-2 \, d x - 2 \, c\right )} - 609 \, e^{\left (-4 \, d x - 4 \, c\right )} + 770 \, e^{\left (-6 \, d x - 6 \, c\right )} - 770 \, e^{\left (-8 \, d x - 8 \, c\right )} + 315 \, e^{\left (-10 \, d x - 10 \, c\right )} - 105 \, e^{\left (-12 \, d x - 12 \, c\right )} - 44\right )}}{d {\left (7 \, e^{\left (-2 \, d x - 2 \, c\right )} - 21 \, e^{\left (-4 \, d x - 4 \, c\right )} + 35 \, e^{\left (-6 \, d x - 6 \, c\right )} - 35 \, e^{\left (-8 \, d x - 8 \, c\right )} + 21 \, e^{\left (-10 \, d x - 10 \, c\right )} - 7 \, e^{\left (-12 \, d x - 12 \, c\right )} + e^{\left (-14 \, d x - 14 \, c\right )} - 1\right )}}\right )} + \frac {2}{3} \, a^{2} b^{3} {\left (15 \, x + \frac {15 \, c}{d} - \frac {2 \, {\left (70 \, e^{\left (-2 \, d x - 2 \, c\right )} - 140 \, e^{\left (-4 \, d x - 4 \, c\right )} + 90 \, e^{\left (-6 \, d x - 6 \, c\right )} - 45 \, e^{\left (-8 \, d x - 8 \, c\right )} - 23\right )}}{d {\left (5 \, e^{\left (-2 \, d x - 2 \, c\right )} - 10 \, e^{\left (-4 \, d x - 4 \, c\right )} + 10 \, e^{\left (-6 \, d x - 6 \, c\right )} - 5 \, e^{\left (-8 \, d x - 8 \, c\right )} + e^{\left (-10 \, d x - 10 \, c\right )} - 1\right )}}\right )} + \frac {10}{3} \, a^{3} b^{2} {\left (3 \, x + \frac {3 \, c}{d} - \frac {4 \, {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} - 3 \, e^{\left (-4 \, d x - 4 \, c\right )} - 2\right )}}{d {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} - 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} - 1\right )}}\right )} + 5 \, a^{4} b {\left (x + \frac {c}{d} + \frac {2}{d {\left (e^{\left (-2 \, d x - 2 \, c\right )} - 1\right )}}\right )} + a^{5} x \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.37, size = 158, normalized size = 0.99 \[ x\,{\left (a+b\right )}^5-\frac {{\mathrm {coth}\left (c+d\,x\right )}^3\,\left (10\,a^3\,b^2+10\,a^2\,b^3+5\,a\,b^4+b^5\right )}{3\,d}-\frac {{\mathrm {coth}\left (c+d\,x\right )}^5\,\left (10\,a^2\,b^3+5\,a\,b^4+b^5\right )}{5\,d}-\frac {{\mathrm {coth}\left (c+d\,x\right )}^7\,\left (b^5+5\,a\,b^4\right )}{7\,d}-\frac {b^5\,{\mathrm {coth}\left (c+d\,x\right )}^9}{9\,d}-\frac {b\,\mathrm {coth}\left (c+d\,x\right )\,\left (5\,a^4+10\,a^3\,b+10\,a^2\,b^2+5\,a\,b^3+b^4\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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